Question

tan x=n tan y n in R ' then the maximum value of sec^(2)(x+y) is equal to qquad ((n+1)^(2))/(2n) 2) ((n+1)^(2))/(n) 3) ((n+1)^(2))/(2) 4) ((n+1)/(4n)​

Answer 1

Answer:

Let, z=sec2(x−y)=1+tan2(x− y) ⇒z=1+(1+tanxtanytanx−tany)2=1+(1+n tan2yntany−tany)2

Step-by-step explanation:

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