Question

tan x=n tan y n in R ' then the maximum value of sec^(2)(x+y) is equal to
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Answer 1

Answer:

If tanx=ntany,n∈R+, then the maximum value of sec2(x-y) is equal to (a)(n+1)22n (b) (n+1)2n (c)(n+1)22 (d) (n+1)24n. So, option d is the correct option.

Step-by-step explanation:

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