Question

tan x = p/q then psinx-qcosx/psinx+qcosx=?​

Answer 1

Answer:

(p^2 - q^2)/(p^2 + q^2)

Step-by-step explanation:

in equation make tanx by dividing cosx.

then put value of tanx.

hope this helped you

Answer 2

Answer:

Step-by-step explanation:

given: tan x=p/q.

psinx-(q/pxq/p)+qcosx

now multiplying and dividing by cosx

1/cosx(ptan-q^2/p^2+q)

secx(pxp/q-q2/p2+q)

secx(p2/q-q2/p2+q)..............(i)

by the law of trigonometry

tan^2x =sec^2x-1

p2/q2+1=sec^2x

secx =root((p2+q2)/q2)

now putting the value of secx in equation (i) we get,

root((p2+q2)/q2)*(p2/q-q2/p2+q)

...........and now solve it by taking common denominator....