tan x +sin x / tan x-sin x= sec +1/sec x-1
prove this
Answers
Answered by
0
Step-by-step explanation:
sorry bye gn....
Hi,
Sin 18°/cos 72° + √3 [tan10 tan 30 tan 40 tan 50 tan 80]
=Sin 18°/cos(90-72) + √3 [tan10 tan 30 tan 40 tan(90-50) tan(90-80)]
=Sin 18°/Sin 18 + √3 [tan10 tan 30 tan 40 cot40 cot10]
=1 + √3 [tan10 tan 30 tan 40 1/tan40 1/tan10]
=1 + √3 [tan 30]
=1 + √3 [1/√3]
=1 + 1 = 2
mark as brainliest!!
Answered by
3
hope this solution helps you.
Attachments:
Similar questions