Question

tan x +sin x / tan x-sin x= sec +1/sec x-1
prove this​

Answer 1

Step-by-step explanation:

sorry bye gn....

Hi,

Sin 18°/cos 72° + √3 [tan10 tan 30 tan 40 tan 50 tan 80]

=Sin 18°/cos(90-72) + √3 [tan10 tan 30 tan 40 tan(90-50) tan(90-80)]

=Sin 18°/Sin 18 + √3 [tan10 tan 30 tan 40 cot40 cot10]

=1 + √3 [tan10 tan 30 tan 40 1/tan40 1/tan10]

=1 + √3 [tan 30]

=1 + √3 [1/√3]

=1 + 1 = 2

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Answer 2

hope this solution helps you.