tan x+tan 4x+tan 7x = tan x ×tan 4x ×tan 7x
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Your Question is if (tanx+tan4x+tan7x) is equal to (tanx × tan4x × tan7x) , find the value of x. ?
since we know that :-----
tan(A+B+C)=(tanA+tanB+tanC-tanA*tanB*tanC)/1-(tanA*tanB+tanB*tanC+tanC*tanA)
And,
If a+b+c is n(π) ,, n belongs to N then
tan(A+B+C) = 0
so,
if , tan(A+B+C) = 0
(tanA+tanB+tanC-tanA*tanB*tanC) = 0
tanA+tanB+tanC = tanA*tanB*tanC
Therefore ,
x + 4x + 7x = nπ
12x = nπ
x = (nπ)/12 (Ans)
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