Question

tan (x+y)= tan x + tan y / 1- tan x tan y .. where x = pie/4 and y = pie/6 classs 11 .. formula deriving based question​

Answer 1

Step-by-step explanation:

x

2

−1(1−a)x+a

3

=0

x+y=

6

π

⇒tan(x+y)=tan(

6

π

)

⇒

1−tanx.tany

tanx+tany

=

3

1

⇒tanx+tany=

3

1

(1−tanx.tany)=

3

1

(1−a)

So equation with roots tanx,tany is

x

2

−(tanx+tany)x+(tanx.tany)=0

⇒

3

x

2

−(1−a)+a

3

=0