tan(x-y)+tan(y-z)+tan(z-x)=tan (x-y)tan(y-z)tan(z-x)
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HELLO DEAR,
we know the formula of tan(A + B + C) is:
nos, using above formula,
putting (A = x - y , B = y - z , C = z - x)
we get,
tan{(x - y) + (y - z) + (z - x)} = tan(x - y + y - z + z - x)
=tan0 = 0 [as, we know tan0° = 0]
0 = tan(x - y) + tan(y - z) + tan(z - x) - tan(x - y)*tan(y - z)*tan(z - x)
on transforming,
we get,
[tan(x - y) tan(y - z) tan(z - x) = tan(x - y) + tan(y - z) + tan(z - x).
I HOPE ITS HELP YOU DEAR,
THANKs
antarpreet95:
thank you so much
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