Question

tan(x-y)+tan(y-z)+tan(z-x)=tan (x-y)tan(y-z)tan(z-x)

Answer 1

HELLO DEAR,

we know the formula of tan(A + B + C) is:

nos, using above formula,

putting (A = x - y , B = y - z , C = z - x)

we get,

tan{(x - y) + (y - z) + (z - x)} = tan(x - y + y - z + z - x)

=tan0 =  0   [as, we know tan0° = 0]

0 = tan(x - y) + tan(y - z) + tan(z - x) - tan(x - y)*tan(y - z)*tan(z - x)

on transforming,

we get,

[tan(x - y) tan(y - z) tan(z - x) = tan(x - y) + tan(y - z) + tan(z - x).

I HOPE ITS HELP YOU DEAR,

THANKs