Question

tan0/1-coto
+ coto/1- tano = 1+ seco × coseco
prove it​

Answer 1

Step-by-step explanation:

This is solution for your question

Answer 2

Answer: tanФ/1-cotФ + cotФ/1-tanФ = 1+ secФ× cosecФ

Step-by-step explanation:

tanФ/1-cotФ + cotФ/1-tanФ = 1+ secФ× cosecФ

Taking L.H.S.-

= tanФ/1-(1/tanФ) + (1/tanФ)/1-tanФ

= tan²Ф/tanФ-1 + 1/tanФ(1-tanФ)

= 1-tan³Ф/tanФ(1-tanФ)

= (1-tanФ) (1+tanФ+tan²Ф)/tanФ(1-tanФ)   (∵a³-b³=(a-b) (a²+ab+b²)

= sec²Ф +tanФ/tanФ    (∵1+ tan²Ф = sec²Ф)

= 1+ sec²Ф/tanФ

= 1+ 1/cosФ×sinФ

= 1+secФ×cosecФ

= R.H.S.

Hence Proved

To learn more about Trigonometry Concepts given below:

https://brainly.in/question/1210124

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