tan0 =1 then value of 0 is
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The value of zero will be 1/0 that is not defined.
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tan 0=1
sin0/cos0=1
sin0=cos0_eq1
So now,sin0+coso
=sin0+sin0(from eq_1)
=2sin0
And seco+ciseco
= 1/cos0+1/sin0
=sin0+cos0÷sino.cos0
=sin0+sin0÷sin0.sin0
=2sin0/sin^20
= 2/sin0
Now, sin0+cos0÷sec0+coseco
=2sin0÷2/sin0
=2sin0xsin0/2
=sinOxsin0
=sin^20(ans)
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