Question

tan0 + sin0/ tan0 - sin0 =
sec9 +1 / sec0 -1 .​

Answer 1

Step-by-step explanation:

3 / 3 I _ smK—n—B)=y—,=—=—cos0 cosK—n —Q)=—=—y=-Sin9 r r 2 I“ 7' 3n ' — 3n ' _ tan[— —0)=y—I=—=cot0 cot[——9)=x—=—=tan9 x ...

i hope it's helpful to u. ❤

Answer 2

hope it helps you dear xd