Tan1.tan2.tan3.....tan89
adithya33:
what I want to find??
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HEYA!
tan 1 ° × tan 2° ...... ........... tan 88° × tan89°
= tan (90° - 89° ) × tan (90°-88°) ....tan 88° × tan 89°
= cot 89° × cot 88° .... tan88° × tan 89°(complementary angles)
= cot89° × tan 89° × ...... cot 88° × tan 88°
= 1 × ..... × 1 (cot ¤ × tan¤ = 1 )
= 1
Hence 1 is the answer.
Hope it helps!
tan 1 ° × tan 2° ...... ........... tan 88° × tan89°
= tan (90° - 89° ) × tan (90°-88°) ....tan 88° × tan 89°
= cot 89° × cot 88° .... tan88° × tan 89°(complementary angles)
= cot89° × tan 89° × ...... cot 88° × tan 88°
= 1 × ..... × 1 (cot ¤ × tan¤ = 1 )
= 1
Hence 1 is the answer.
Hope it helps!
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