Tan1 tan2 tan3...............tan98=0 prove
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tan1.tan2.........tan98but tan 98 can be written as cot 1[tan(100-2)=cot 1] by tan(90-theta)=cot(theta)likewise......,tan 88 =cot 2tan 87= cot 3................up to tan 46=cot 44then middle one is tan 45 =1so it is tan1.tan2...........tan44.tan 45.cot44..............cot1tan and cot cancel out by[tan (theta)*cot(theta)=1so ....remaining is 1answer =1
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