tan¹(x+1)+tan ¹(x-1)= tan -18 11 then 'x' is
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tan−1(x+1)+tan−1318
tan−1(1−(x+1)(x−1)x+1+x−1)=tan−1318
⇒tan−1(1−x2+12x)=tan−1318
⇒2−x22x=318
⇒62x=16−8x2
⇒8x2+62x−16=0
⇒4x2+31x−8=0
⇒4x2+32x−8=0
⇒4x(x+8)−1(x+8
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