tan10, tan15, tan75, tan80, =?
Answers
Answered by
0
Answer:
tan10---0.1763
tan 15---0.2679
tan 75---3.732
tan80---5.671
Answered by
34
Answer: 1
Explanation:
We know, tan A = cot (90 - A)
So,
tan10° tan15° tan75° tan80°
= cot(90° - 10°) tan80° × cot(90° - 15°) tan75°
= 1/tan(80°) × tan80° × 1/tan(75°) × tan75°
= 1
More:
If θ1 + θ2 = 90°,
then
- tanθ1 . tanθ2 = 1 &
- cotθ1 . cotθ2 = 1.
So, using this, you can easily deal with these questions.
(tan10° . tan80°) . (tan15° . tan75°)
= 1 × 1 = 1.
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