tan17°=x then tan 163°-tan107°÷1+tan163°tan107°=?
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Answered by
18
tan 17 = x
tan 163 == tan(180-17) => -tan 17
tan 107 == tan(180-73) => -tan 73
now
tan 107 - tan 163/1+ tan 107 tan 163
=> tan 17 -tan 73/ 1 +tan73tan17( since cot 73 = x .so tan 73 = 1/x)
=> -x +1/x/1+1
=> 1-x^2/2x
will be the answer.
tan 163 == tan(180-17) => -tan 17
tan 107 == tan(180-73) => -tan 73
now
tan 107 - tan 163/1+ tan 107 tan 163
=> tan 17 -tan 73/ 1 +tan73tan17( since cot 73 = x .so tan 73 = 1/x)
=> -x +1/x/1+1
=> 1-x^2/2x
will be the answer.
Answered by
1
Answer:
tan 17 = x
tan 163 == tan(180-17) => -tan 17
tan 107 == tan(180-73) => -tan 73
now
tan 107 - tan 163/1+ tan 107 tan 163
=> tan 17 -tan 73/ 1 +tan73tan17( since cot 73 = x .so tan 73 = 1/x)
=> x +1/x/1+1
=> 1+x^2/2x
will be the answer.
Step-by-step explanation:
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