tan18 + tan27 + tan18 × tan 27 =?
Answers
Answered by
0
Answer:
tan18°+tan27°+tan18°tan27°=0
tan(18+27)=
\frac{ \tan(18) + \tan(27) }{1 - \tan(18) \tan(27) }1−tan(18)tan(27)tan(18)+tan(27)
\tan(45) = \frac{ \tan(18) + \tan(27) }{1 - \tan(18) \tan(27) }tan(45)=1−tan(18)tan(27)tan(18)+tan(27)
1 - \tan(18) \tan(27) = \tan(18) + \tan(27)1−tan(18)tan(27)=tan(18)+tan(27)
1 = \tan(18 + 27) + \tan(18) \tan(27)1=tan(18+27)+tan(18)tan(27)
= 1=1
please mark me brainliest
Similar questions
Accountancy,
3 months ago
Social Sciences,
3 months ago
Computer Science,
7 months ago
History,
10 months ago
English,
10 months ago