Tan189 = Cos36 - Sin36 / Cos36 + Sin36
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Answered by
4
2. Show that tan(189°) = cos(36°)−sin(36°)? cos(36°)+sin(36°)
Sol.6)
1.tan (13) = tan(195°) 12
tan(180° + 15°) = tan(15°)
tan(45° − 30°) tan(45°)−tan(30°)
1+tan(45°) tan(30°)
1 √3=√3−1
1+ 1 √3+1 √3
√3−1 × √3−1
√3+1 √3−1 3+1−2√3
3−1
4−2√3 = 2√3 ans. 2
= =
= =
= = =
= =
= =
=
= cos(36°)−sin(36°) ans. cos(36° )+sin(36° )
1−
L.H.S tan(189°) = tan(180° + 9°) tan(45°)−tan(36°)
2.
tan 9 ........... tan(45° − 36°)
sin(36°) 1− °
cos(36 ) 1+sin(36°) cos(36°)
°
1+tan(45°) tan(36°) 1−tan(36°)
1+tan(36°)
Sol.6)
1.tan (13) = tan(195°) 12
tan(180° + 15°) = tan(15°)
tan(45° − 30°) tan(45°)−tan(30°)
1+tan(45°) tan(30°)
1 √3=√3−1
1+ 1 √3+1 √3
√3−1 × √3−1
√3+1 √3−1 3+1−2√3
3−1
4−2√3 = 2√3 ans. 2
= =
= =
= = =
= =
= =
=
= cos(36°)−sin(36°) ans. cos(36° )+sin(36° )
1−
L.H.S tan(189°) = tan(180° + 9°) tan(45°)−tan(36°)
2.
tan 9 ........... tan(45° − 36°)
sin(36°) 1− °
cos(36 ) 1+sin(36°) cos(36°)
°
1+tan(45°) tan(36°) 1−tan(36°)
1+tan(36°)
Answered by
1
Step-by-step explanation:
use formula
=Cos36 ,+sin36
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