Question

tan1º. tan2°. tan3°. tan4°......tan87°.tan88°. tan89° का मान कितना होगा ?​

Answer 1

Answer:

1

Step-by-step explanation:

tan1. tan2. tan3. tan4. ........tan87. tan88.tan89

We know that Tan Ø = Cot (90-Ø)

So,

→Tan 1. Tan2. Tan3........... cot(90-87) . Cot (90-88) . cot (90-89)

→Tan1. Tan2. Tan3.......... cot 3. cot 2. cot1

Now, we know that

Now, we know that cot Ø =1/Tan Ø

→Tan1. Tan2. Tan3. ........1/Tan3. 1/Tan2.1/Tan1

Now all the terms will be divided by each other, hence the answer left is 1.

Answer 2

Answer:

The answer to this question is 1

Step-by-step explanation:

So,

Tan 1.Tan 2.............Tan 89 can be written as cot 1[tan(90-1)=cot 1] by tan(90-theta)=cot(theta).

The same way,

Tan 88= Cot 2

and

Tan 87=Cot 3

The middle equation is  Tan 45= 1

Therefore,the equation will come as,

Tan 1. Tan 2.............. Tan 44. Tan 45.Cot 44 ................Cot 1

Using the equation,[tan (theta)*cot(theta)=1 we can cancel out Tan and Cot.

If Tan and Cot get cut the remaining number is 1.

Hence, The answer is 1.

Hope this helps you.....