tan² A – 5 sec² A + 1 is equal to
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3
Answer:
tan²A - 5 sec²A + 1
= tan²A - 5sec²A + sec²A - tan²A
= - 4sec²A
Step-by-step explanation:
Hope it is the correct answer.
Answered by
7
ANSWER
5tan 2 θ−5sec 2 θ
⇒5(tan 2 θ−sec 2 θ)=5(−1)=−5 [∵1tan 2 θ=sec 2 θ]
Hence, the answer is −5.
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