Question

tan2 A + cot2 A + 2 = sec2 A cosec2 A​

Answer 1

Answer:

PLZ MARK AS BRAINLIEST!!!!!!!!

Answer 2

Answer:

HEY MATE HERE'S YOUR ANSWER

Step-by-step explanation:

$lhs = { \tan }^{2} a + {cot}^{2} a + 2 \\ = {tan}^{2} a + 1 {cot}^{2} a + 1 \\ = { \sec }^{2}a + { \csc }^{2} a \\ = \frac{1}{ { \cos }^{2} a} + \frac{1}{{ \sin }^{2} a } \\ = \frac{ { \sin }^{2} a + {cos}^{2}a }{ { \cos }^{2}a \: \: \: \: {sin}^{2}a } \\ = \frac{1}{ {cos}^{2} a \: \: \: \: {sin}^{2} a} \\ = {sec}^{2} a {csc}^{2} a = rhs$

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