Question

tan2 q- sin2q=tan2qsin2q​

Answer 1

taking LHS,

tan²q - sin²q.

tan²q -(1-cos²q).

tan²q - 1+ cos²q.

sec²q+cos²q.

taking RHS,

tan²q . sin²q.

(1+sec²q).(1-cos²q)

1+cos²q + sec²q - sec²qcos²q.

1 + cos²q+sec²q - 1.

cos²q+ sec²q.

LHS=RHS.

hence proved.