tan² sec²a +1=2
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0
3(sec
2
θ+tan
2
θ)=5⇒tan
2
θ+1+tan
2
θ=
3
5
⇒2tan
2
θ+1=
3
5
⇒tan
2
θ=
3
1
=(
3
1
)
2
=(tan
6
π
)
2
⇒tanθ=±tan
6
π
⇒θ=nπ±
6
π
Answered by
0
Answer:
The answer for your question is \large\boxed{\textbf{\textit{-1}}}
The trigonometric identity used is
{ \sec }^{2}A \: - \: { \tan }^{2}A \: = 1
For the whole explanation, please check the attachment.
If any doubts, then please put them in the comments.
Step-by-step explanation:
Attachments:
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