Math, asked by Anonymous, 1 year ago

tan²-sin²=sin⁴×sec²​

Answers

Answered by rishabh1894041
2

Step-by-step explanation:

 {tan}^{2}  \alpha  -  {sin}^{2}  \alpha  =  {sin}^{4}  \alpha  \times  {sec}^{2}  \alpha  \\  \\ L.H.S. \\  {tan}^{2}  \alpha  -  {sin}^{2}  \alpha  \\  \frac{ {sin}^{2}  \alpha }{ {cos}^{2} \alpha  }  -  {sin}^{2}  \alpha  \\  {sin}^{2}  \alpha ( \frac{1 -  {cos}^{2}  \alpha }{ {cos}^{2} \alpha  } ) \\   \frac{ {sin}^{4}  \alpha }{ {cos}^{2}  \alpha }  \\  {sin}^{4 }  \alpha  \times  {sec}^{2}  \alpha  \\  \\ Hence \: proved \\ Hope \: it \: will \: help \: you.

Similar questions