Question

tan2 theta - sin2 theta

Answer 1

Tan2a = 2 tan a/( 1- tan^2a)

Sin 2a = 2 tan a/( 1+ tan^2a)

tan2a - Sin2a = 2tana( 1/( 1- tan^2a). - 1/( 1+ tan^2a)

= 2 tan a(2 tan^2 a)/) 1- tan^4a)

= 4 tan^3 a)/ ( 1- tan^4 a)

Answer 2

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