tan2 x – sin2x = tan2 x sin2 x
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We have to prove that (tan x)^2 - (sin x)^2 = (tan x)^2 * (sin x)^2
Start from the left hand side:
(tan x)^2 - (sin x)^2
use tan x = sin x / cos x
(sin x)^2/(cos x)^2 - (sin x)^2
=> [(sin x)^2 - (sin x)^2*(cos x)^2]/(cos x)^2
=> (sin x)^2[1 - (cos x)^2]/(cos x)^2
=> (sin x)^2 * [(sin x)^2 / (cos x)^2]
=> (tan x)^2 * (sin x)^2
which is the right hand side.
This proves that (tan x)^2 - (sin x)^2 = (tan x)^2 * (sin x)^2
HOPE THIS HELPS PLZ MARK AS BRAINLIEST
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RHS
LHS
= RHS
since, LHS = RHS
hence,
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