Tan20=A find value of tan160-tan110÷1+tan160.tan110
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Given tan20 = p.tan 160 = tan (180 - 20) = - tan20 = -p.tan 110 = tan (90+20) = -cot 20 = -1/p.tan 60 = sqrt(3). We know this.
So (tan160 - tan110) / (1 + tan60× tan110) = (-p +1/p)/(1+ sqrt3 × -1/p)= (1-p^2)/(p - sqrt3) is it helpful.......!!
So (tan160 - tan110) / (1 + tan60× tan110) = (-p +1/p)/(1+ sqrt3 × -1/p)= (1-p^2)/(p - sqrt3) is it helpful.......!!
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