tan20.tan40 = 1, then the value of tan30 ?
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THE VALUE OF tan30 is between 0 and 1
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Answer:3 tan2θ=1tan4θ=cot4θ ⇒tan2θ=tan(90∘−4θ) ⇒2θ=90∘−4θ⇒6θ=90∘⇒θ= 15∘ ∴tan3θ=tan45∘=1
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