tan20+tan40+3^1/2.tan20.tan40=?
Attachments:
Answers
Answered by
16
Tan60 = (tan(20+40)
√3 ={ tan20 + tan40 }/{1- tan20.tan40}
Tan20 + tan40 = √3 - √3tan20.tan40
Tan20 + tan40 + √3tan20.tan40 = √3
√3 ={ tan20 + tan40 }/{1- tan20.tan40}
Tan20 + tan40 = √3 - √3tan20.tan40
Tan20 + tan40 + √3tan20.tan40 = √3
joshisameer343:
how can you just do it.... i cant solve trigonometry
Just because I remember the all formula and apply .. here in question we need tan40 , tan20 .. we know the value of tan60 ..And the formula of tan(a+b) ..
okay
but approach is hard for new problems
Practice 50-100 problems . You will also familiar will all question and solutions. After that every problem will be easy for you. Only thing is practice nothing else.
okay
thanx
Answered by
5
Answer:
W.k.t
Tan60=√3
Tan(20+40)=√3
Tan20+Tan40/1-Tan20.Tan40=√3
Tan20+Tan40=√3(1-Tan20.Tan40)
Tan20+Tan40=√3-√3Tan20.Tan40
Tan20+Tan40+√3Tan20.Tan40=√3
Attachments:
Similar questions