tan20+tan40+√3 tan 20 ×tan 40
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it is given that tan20° + tan40° + √3 tan20° × tan40°
now tell me , can we write tan60° = tan(40° + 20°) ? of course yes !
now use the formula, tan(A + B) = (tanA + tanB)/(1 - tanA.tanB)
so, tan(40° + 20°) = (tan40° + tan20°)/(1 - tan40°.tan20°)
now, tan60° = (tan40° + tan20°)/(1 - tan40°.tan20°)
or, √3(1 - tan40°. tan20°) = tan40° + tan20°
or, √3 - √3tan20°. tan40° = tan40° + tan20°
or, √3 = tan20° + tan40° + √3 tan20° . tan40°
hence, value of (tan20° + tan40° + √3tan20°. tan40°) = √3
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