tan20° + 4 sin20°= 3^1/2
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Answer:
√3
Step-by-step explanation:
sin20/(cos20+4sin20 )
(sin20+4sin20cos20)/cos20
2sinAcosA=sin2A
sin(C−D)=sinCcosD−cosCsinD
sin(C+D)=sinCcosD+cosCsinD
(sinn20+2sin40)/cos20
sin20+2sin(60−20)cos20
(sin20+2{sin60cos20−cos60sin20})/cos20
(sin20+2sin60cos20−sin20)/cos20
(2sin60cos20)/cos20
2sin60
2.√3/2
√3
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