Math, asked by charithar526, 9 months ago

tan20°-tan80°+√3=?

correct answer will be marked as brainliest​

Answers

Answered by saniyabanu580
0

Answer:

tan20tan80cot50

=

tan(60−10)

tan(30−10)tan(90−10)

=

1+tan60tan10

tan60−tan10

1+tan30tan10

tan30−tan10

cot10

=

tan10

1+

3

tan10

3

−tan10

1+

3

1

tan10

3

1

−tan10

=

tan10⋅

1+

3

tan10

3

−tan10

3

+tan10

1−

3

tan10

=

tan10(3−tan

2

10)

1−3tan

2

10

=

3tan10−tan

3

10

1−3tan

2

10

=

tan3(10)

1

=

tan30

1

=

3

Answered by anithareddy0789
1

Answer:

Idk

Step-by-step explanation:

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I know it's not the answer but I want brainliest because my brainliest are only 3 so Mark as brainliest

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