Tan22+tan23+tan22+tan23=1 prove that
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Answered by
2
Hi,
Here is the answer to your query:-
▶Formula used:(from trigonometry)
✅Tan(A+B)=(tanA+tanB)/(1-tanA*tanB)
Let A=22°,B=23°
Tan(22°+23°)=(tan22°+tan23°)/(1-tan22°×tan23°)
From trigonometry, we know tan45°=1
Therefore tan(45°)=1=(tan22°+tan23°)/(1-tan22°tan23°)
=> 1-tan22°tan23°=tan22°+tan23°
=> tan22°+tan23°+tan23°tan22° =1
Hence proved.
✅Thanks
@SHIVAM
Here is the answer to your query:-
▶Formula used:(from trigonometry)
✅Tan(A+B)=(tanA+tanB)/(1-tanA*tanB)
Let A=22°,B=23°
Tan(22°+23°)=(tan22°+tan23°)/(1-tan22°×tan23°)
From trigonometry, we know tan45°=1
Therefore tan(45°)=1=(tan22°+tan23°)/(1-tan22°tan23°)
=> 1-tan22°tan23°=tan22°+tan23°
=> tan22°+tan23°+tan23°tan22° =1
Hence proved.
✅Thanks
@SHIVAM
Answered by
0
tan22+cot(90-68)+tan23+cot(90-67)=1
tan22+cot22+tan23+cot230=1
tan22+1/tan22+tan23+1/tan23 =1
1 = 1
tan22+cot22+tan23+cot230=1
tan22+1/tan22+tan23+1/tan23 =1
1 = 1
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