tan25. tan60. tan65. tan75
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Recall the identity \tan(90-\theta)=\cot(\theta) noticing that 65=90-25 and 75=90-15 :
\tan(15)\tan(25)\tan(60)\tan(65)\tan(75)\\=\tan(15)\tan(25)\tan(60)\tan(90-25)\tan(90-15)\\=\tan(15)\tan(25)\tan(60)\cot(25)\cot(15)\\=\tan(15)\cot(15)\tan(25)\cot(25)\tan(60)\\=\tan(60)\\=\sqrt{3}
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Thanks for the question.
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√3(√3+1/√3-1) is the answer
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