tan²60+4cos²45+3cos²60+2cos²90/2cosec30+3sec60-(7/3)cos²30
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Answer:
tan60=√3
cos45=1/√2
cos60=1/2
cos90=0
cosec30=2
sec60=2
cos30=√3/2
tan²60+4cos²45+3cos²60/2cosec30+3sec60-(7/3)cos30
=3+4×1/2+3×1/4+2×0/2×2+3×2-(7/3)×3/4
=3+2+3/4+0+6-21/12
=11-13/12
=(132-13)/12
=119/12
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