Question

Tan²60+4cos²45+3sec²0+5cos²90/cosec30+sec60-cot²30

Answer 1

Hey friend!!!

$\frac{\tan ^{2} (60) + 4 \cos {}^{2} (45) + 3 \sec {}^{2} (0) + 5 \cos {}^{2} (90) }{ \csc(30) + \sec(60) - \cot {}^{2} (30) } \\ \\ = \frac{3 + 4 \times \frac{1}{2} + 3 \times 1 + 5 \times 0 }{ 2 + 2 - 3 } \\ \\ = \frac{3 + 2 + 3 }{ 1} \\ \\ = 8 \\ \\ here..... \\ \\ \tan( 60) = \sqrt{3} ..... \tan ^{2} (60) = 3 \\ \\ \cos(45) = \frac{1}{ \sqrt{2} } ..... \cos {}^{2} (45) = = \frac{1}{2} \\ \\ \sec(0) = 1..... \sec {}^{2} (0) = 1 \\ \\ \cos(90) = 0 \\ \\ \csc(30) = 2 \\ \\ \sec(60) = 2 \\ \\ \cot(30) = \sqrt{3} ..... \cot {}^{2} (30) = 3$
Hope it helps