Question

Tan²60⁰+4sin²45⁰+3sec²30⁰+5cos²90⁰÷cosec30⁰+sec60⁰-cot²30⁰

Answer 1

Answer:

17/3

Step-by-step explanation:

Tan²60⁰+4sin²45⁰+3sec²30⁰+5cos²90⁰÷cosec30⁰+sec60⁰-cot²30⁰

=(root 3)^2+4(1)^2+3(1/2)^2+5(0)^2/(root 3/2)^2+(root 3/2)^2-(root 3)^2

=(3+4+3/2+0)/(3/4+3/4-3)

=(7+3/2)/(6/4-3)

=(17/2)/(3-6/2)

=(17/2)/(3/2)

=17/3

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