tan27° tan 32°+tan 32°tan 31°+tan31° tan27°
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The value of tan27° tan 32°+tan 32°tan 31°+tan31° tan27° is 1
Given,
tan27° tan 32°+tan 32°tan 31°+tan31° tan27°
To Find,
We have to find the Value of tan27° tan 32°+tan 32°tan 31°+tan31° tan27°
Solution,
From given, we have, 27+32+31=90
So, we consider this form,
S=tanAtanB+tanBtanC+tanCtanA.......(1)
⇒S=tanAtanB+tanC(tanA+tanB)
where A+B+C=90, and C=90−(A+B)
and, tanC=tan(90−A−B)=cot(A+B)= 1/tan (A+B)
or, tanC= 1−tanAtanB/ tanA+ tanB
or, tanC(tanA+tanB)=1−tanAtanB..........(2)
Now, from (1) and (2)
S=tanAtanB+tanC(tanA+tanB)
=tanAtanB+(1−tanAtanB)
=1
Hence, the value of tan27° tan 32°+tan 32°tan 31°+tan31° tan27° is 1
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