tan²A ( 1-sin²A) = 1-cos²A. please give the answer I will mark brainliest. if picture possible please
Answers
Answered by
0
Answer: ({2}A - Cosec^{2}A =\ \textgreater \ { Cot^{2}A - Cosec^{2}A } + Sec^{2}A [/tex]
Hence proved that
LHS = RHS
Step-by-step explanation:
Answered by
0
Step-by-step explanation:
tan^2A(1-sin^2A)=sin^2A/cos^2A×cos2A=sin^2A=1-cos3A
Attachments:
Similar questions