Question

tan²A ( 1-sin²A) = 1-cos²A. please give the answer I will mark brainliest. if picture possible please​

Answer 1

Answer: ({2}A - Cosec^{2}A =\ \textgreater \ { Cot^{2}A - Cosec^{2}A } + Sec^{2}A [/tex]

Hence proved that

LHS = RHS

Step-by-step explanation:

Answer 2

Step-by-step explanation:

tan^2A(1-sin^2A)=sin^2A/cos^2A×cos2A=sin^2A=1-cos3A