tan2A=2tanA/1-tan^2A, then prove that tan15°=2-sq root of 3
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let a=15
tan30=(2tan15)/(1-tan^2 15)....let tan15=t
(1/√3)=2t/1-t^2
1- t^2=2√3t
t^2+2√3t-1=0
solve this quadratic.. u will get t I. e. tan15
tan30=(2tan15)/(1-tan^2 15)....let tan15=t
(1/√3)=2t/1-t^2
1- t^2=2√3t
t^2+2√3t-1=0
solve this quadratic.. u will get t I. e. tan15
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