tan2A = 2tanA÷1-tan^2A where A = 30°
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Answer:
proved
Step-by-step explanation:
L.H.S
Tan 2A = tan 2*30= tan 60= √3
R.H.S
2tan A / 1-tan²A = 2tan30 / 1-tan²30
=2*(1/√3) / 1-(1/√3)²
=(2/√3) / (2/3)
=2*3/2√3
=√3*√3/√3
=√3
L.H.S=R.H.S
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