Tan2A=cot(A-18) where 2A is an acute angle find the value of A
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tan 2A=cot(A-18)..........1
tan 2A=cot(90-2A)..........2
From 1 and 2
cot(A-18)=cot(90-2A)
A-18=90-2A
3A=108
A=36°
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