Question

tan2A=cot(A-18°) where 2A is a acute angle,then find the value of A..

Answer 1

Hi there !

here is the solution:

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we convert tan to cot

cot(90 - 2A) = cot ( A - 18)

now remove the cot, and equate the multiples

90 - 2A = A - 18

Therefore, A = 108/3 = 36° Ans

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I HOPE THIS HELPS...

Answer 2

 Solution:

It is given that tan2A=cot(A−18°)

 ⇒tan2A=cot(90° −(108° −A))

⇒tan2A=tan(108° −A)        

{°•° cot(90° −A)=tan(A)}

 ⇒2A=108° −A

 ⇒3A=108°

 ⇒A=108°/3 =36°

Thanks ☺