Math, asked by rakesh8495, 3 months ago

tan²a+cot²a=2 तो a=? ​


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Answers

Answered by raosabh1255
2

Answer:

tan2a + cot2a + 2

= sec2a - 1 + cosec2a - 1 + 2

= sec2a - 2+2 + cosec2a

=sec2a + cosec2a


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Answered by dishar637
1

Step-by-step explanation:

LHS =tan2A+cot2A+2

=sec2A−1+cosec2A−1+2

= sec2 A + cosec2 A

=1cos2A+1sin2A

=sin2A+cos2Acos2A⋅sin2A

=1cos2A⋅sin2A

=1cos2A×1sin2A

= sec2 A. cosec2 A = RHS


rakesh8495: व्यापक मान क्या होगा
dishar637: matlab
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