Question

tan²A +sec²A = 5 then what is the value of sec A

Answer 1

tan²A +sec²A = 5

tan²A + (tan²A + 1) = 5

2tan²A = 5 - 1 = 4

tan²A = 4/2 = 2

sec²A = tan²A +1 = 2+1 = 3

sec A = √3 and -√3

Answer 2

We know that,

→ sec²A = tan²A + 1

→ tan²A = sec²A - 1
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tan²A + sec²A = 5

=> ( sec²A - 1 ) + sec²A = 5

=> 2sec²A - 1 = 5

=> sec²A = 5 + 1/2

=> sec²A = 6/2

=> sec²A = 3

=> sec A = ± √3

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