Math, asked by rohannanda2904, 1 month ago

tan²A sec²B – sec²A tan²B is equal to
(1) tan²A- tan²B
(2) tan²B – tan²A
(3) tan²B + tan²A
(4) tan²B tan²A

tell me correct ans and how?

Answers

Answered by mr8563554

0

Answer:

I don't know sorry don't fell bad

good night

Answered by chetansain4123

2

Answer:

the answer is 4 option it's eazy

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