Math, asked by rajakansari, 1 year ago

tan2a+sin2a=4tana/1-tan^4a

Answers

Answered by vishalsaini0491

19

Answer:

tan2a=2tana/(1-tan ^2a) -------eqn 1

sin2a=2tana/(1+tan^2a)----eqn2

adding eqn 1 and 2 we get required result

Answered by whoseimposter

2

Answer:

LHS:Tan2a+sin2a

:2tana/(1+tan^2a)+2tana/(1+tan^2a)

:4tana/1+tan^2a

rhs prove bahayo

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