Math, asked by jinishbelfin, 10 months ago

tan2A-tan2B=sin2A-sin2B/cos2A*cos2B

Answers

Answered by shatakshi4485

0

Answer:

zu j JBjh. hj 9*9076-8734078hx bs sbsjs

Step-by-step explanation:

svbs sh d sbjs snskshs

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bdbebsi sbsjs d. dbdjnevej e dbwj e djebyeiwjbdbd js e si s sbjwbdhe

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