Math, asked by rajakansari, 11 months ago

tan2A-tanA/tanA=sec^2A​

Answers

Answered by vishalsaini0491
0

Answer:

tan2a= 2 tan a /1-tan^2 a

=tan2a/tana-1

=2/1-tan^2 a -1

=(2-1+tan^2 a)/1- tan^2 a

sec^2 a / 1-tan^2 a

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