tan2Atan3A=1 find the value of A
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Step-by-step explanation:
Given that tan2Atan3A = 1
=> tan2A = cot3A
we know that ,
we know that , tan ( 90 - A) = cot A
we know that , tan ( 90 - A) = cot Athen tan 2A = cot ( 90 - 2A )
so, cot ( 90 - 2A ) = cot 3A
so, cot ( 90 - 2A ) = cot 3A we get ,
so, cot ( 90 - 2A ) = cot 3A we get , 90 - 2A = 3A
so, cot ( 90 - 2A ) = cot 3A we get , 90 - 2A = 3A5A = 90
so, cot ( 90 - 2A ) = cot 3A we get , 90 - 2A = 3A5A = 90A = 18
thanx dear
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