tan²cos-1 1/√3 + cot² sin-1 1/√5=6
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Answer:
Correct option is
C
2
1
(3−
5
)
Given,
y=tan[
2
1
cos
−1
(
3
5
)]
Let, x=cos
−1
(
3
5
)
⇒cosx=
3
5
∴y=tan
2
1
x
y=tan
2
x
y=
1+cosx
1−cosx
=
1+
3
5
1−
3
5
=
3+
5
3−
5
rationalizing the factor, we get,
y=
2
3−
5
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